The first player writes down the name of one of the states of the USA. The second player must either prefix that state name with a different state name that ends with the first letter of the original state name, or must append a different state name that starts with the last letter of the original state name.

For example, if the first player writes down Nevada, the second player can prefix Wisconsin or append Alaska, for instance.

Play continues around all the players, prefixing or appending to the chain at either end, until one player can't think of a state, and they are then eliminated. The next person to have played now starts a new chain, and play continues until only one player is left in - the winner.

No state can be used more than once in a single game.

If you are first to play in a three-player game, how do you play to ensure you win? Assume that the other players play logically and don't collude against you.

As usual you can post your suggested answers as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

Answer at 9.00 on Monday

]]>*I've got ten or more daughters**I've got fewer than ten daughters**I've got at least one daughter*

He then said "Only one of these statements is true. How many daughters do I have?"

How many daughters does the strange man have?

Statement 2 is true if the man has no daughters, one daughter, etc. up to nine daughters.

And statement 1 is true if the man has ten daughters, eleven daughters, etc.

So one, and only one, of statements 1 and 2 is always true. Therefore for the number of daughters the strange man has, one or other of these must be the only true statement.

Thus, for only one of the three statements to be true, statement 3 must be false. That is, he does not have at least one daughter - he has none.

]]>*I've got ten or more daughters**I've got fewer than ten daughters**I've got at least one daughter*

He then said "Only one of these statements is true. How many daughters do I have?"

How many daughters does the strange man have?

As usual you can post your suggested answers as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

Answer at 9.00 on Monday

]]>- CN DRL L - Cinderella
- LD DN - Aladdin
- TR ZN - Tarzan
- D MB - Dumbo
- BMB - Bambi
- ML N - Mulan
- R BNH D - Robin Hood
- P CH NTS - Pocahontas
- HR CLS - Hercules
- CG - Ice Age

- CN DRL L
- LD DN
- TR ZN
- D MB
- BMB
- ML N
- R BNH D
- P CH NTS
- HR CLS
- CG

As usual you can post your suggested answers as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

Answer at 9.00 on Monday

]]>Three people are placed in chairs and blindfolded, and then a hat is placed on each of their heads. The hats are either black or white, and there could be three black hats, three white hats, or two of one colour and one of the other. The hats are picked at random from a bag and placed on heads.

The three blindfolds are removed and each person can now see the other two people, but not themselves or, more importantly, their hat. The people are not allowed to communicate in any way.

Each person can then try to guess the colour hat they are wearing, or they can elect not to guess - a pass. None of the three know what the other two have done.

If one of the people guesses correctly they each win $1 million; if any of the three guess incorrectly they leave with nothing.

They were allowed a meeting beforehand to decide on a method. What is the best method for them to use? Can they guarantee success? Or what is their best percentage chance?

The best method is to agree that anyone who sees two hats of the same colour guesses the other colour, and anyone who sees two hats of different colours passes.

There are eight different combinations - BBB, BBW, BWB, WBB, WWB, WBW, BWW and WWW.

For BBB and WWW the method fails, as all three people will guess, and guess incorrectly.

For the other six combinations one person and one person only will see two hats of the same colour, and will guess correctly. The other two people will see hats of different colours and pass.

Six wins out of eight possible combinations is a win percentage of 75%

]]>

Three people are placed in chairs and blindfolded, and then a hat is placed on each of their heads. The hats are either black or white, and there could be three black hats, three white hats, or two of one colour and one of the other. The hats are picked at random from a bag and placed on heads.

The three blindfolds are removed and each person can now see the other two people, but not themselves or, more importantly, their hat. The people are not allowed to communicate in any way.

Each person can then try to guess the colour hat they are wearing, or they can elect not to guess - a pass. None of the three know what the other two have done.

If one of the people guesses correctly they each win $1 million; if any of the three guess incorrectly they leave with nothing.

They were allowed a meeting beforehand to decide on a method. What is the best method for them to use? Can they guarantee success? Or what is their best percentage chance?

Answer at 9.00 on Monday

]]>Our colleagues have been to a quiz where teams were limited to three, with no exceptions. This did mean that couples who happened to be in the pub could join in, without thinking they were going to be at a disadvantage. However, three is an odd number (in both senses) because it prevents two couples, or mum, dad and the two children, from joining in.

At the other extreme we have seen a team of ten at one quiz. There were several “less than friendly” looks and comments about this from other, more normally sized teams . . . especially when they won!

The best approach is to advertise the team size limit in advance, and four or six are a good limits. In this way a team of ten can’t claim to be unaware, and can’t complain too much when they’re split into two teams. Although on a related note, you should ensure they don’t mark each other’s answers!

Equally, you could suggest to two or three teams of two that they combine forces, especially if you are running out of tables.

]]>Saturn | Earth | Mercury | Venus |

Tennessee | Chester | Viler | Thor |

Jupiter | Moon | Frank | Bairn |

Mars | Neptune | Sun | Satchmo |

Saturn, Thor, Moon and Sun - Give Name to Days of the Week

Venus, Tennessee, Chester and Frank - Williams

Mercury, Jupiter, Mars and Neptune - Planets

Earth, Viler, Bairn and Satchmo - Anagrams of Organs (Heart, Liver, Brain and Stomach)

]]>Saturn | Earth | Mercury | Venus |

Tennessee | Chester | Viler | Thor |

Jupiter | Moon | Frank | Bairn |

Mars | Neptune | Sun | Satchmo |

Answer at 9.00 on Monday

]]>It is very difficult to imagine how they make them, and of course, the process is a closely guarded secret.

The bakery supplies the loaves presliced to the Jolly Quizmaster pub, where they are toasted for breakfast. Each loaf has ten slices.

The various sizes of the slices is very useful for people with different appetites, but confusing for those who like or dislike the crust. Can you help? Which slices have the most and least crust?

Oddly, every slice has the same amount of crust. As the slices get smaller, the increased size of the crust, because of the increasing slope, exactly compensates.

The curved surface of a cylinder the same radius and height as a sphere has the same area as the sphere:

Surface area of Sphere = 4 π r squared

Height of Cylinder = 2 r

Circumference of Cylinder = 2 π r

Surface area of Cylinder = 4 π r squared

And it turns out that all the slices through both also have the same surface area.

]]>It is very difficult to imagine how they make them, and of course, the process is a closely guarded secret.

The bakery supplies the loaves presliced to the Jolly Quizmaster pub, where they are toasted for breakfast. Each loaf has ten slices.

The various sizes of the slices is very useful for people with different appetites, but confusing for those who like or dislike the crust. Can you help? Which slices have the most and least crust?

As usual you can post the answers as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

Answer on 9.00 on Monday

]]>There are nine pictures, each of which represents a person, real or fictional. These nine people can be placed into four pairs of lovers, leaving one odd one out.

You have two find the four pairs of lovers and thus the odd one out. A correct solution will have the four pairs correctly coupled and the odd one out.

NB at the quiz night, because they had less time, only the odd one out had the be specified. As you have more time we think you can provide a full solution.

The pictures can be found here.

From top left to bottom right the people are: (Alfa) Romeo, Cleopatra, Juliet (Phonetic Alphabet), John Smith(s), Paris, Napoleon, Helena (Bonham Carter), Antony (Gormley) and Pocahontas.

The pairs of lovers are:

Romeo & Juliet, Antony and Cleopatra, John Smith & Pocahontas, and Paris & Helena. Leaving Napoleon as the odd one out.

]]>There are nine pictures, each of which represents a person, real or fictional. These nine people can be placed into four pairs of lovers, leaving one odd one out.

You have two find the four pairs of lovers and thus the odd one out. A correct solution will have the four pairs correctly coupled and the odd one out.

NB at the quiz night, because they had less time, only the odd one out had the be specified. As you have more time we think you can provide a full solution.

The pictures can be found here.

As usual you can post the answers as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

Answer on 9.00 on Monday

]]>1. L D YM DNN

Lady Madonna

2. YL L WSB MRN

Yellow Submarine

3. PN NYLN

Penny Lane

4. S GTP P PRSLN LYHR TSC LBBN D

Sgt Pepper's Lonely Hearts Club Band

5. YST RDY

Yesterday

6. GTBC K

Get Back

7. BL DB LD

Ob La Di Ob La Da

8. LTT B

Let It Be

9. GH TDY SWK

Eight Days a Week

10. FLFN

I Feel Fine

]]>1. L D YM DNN

2. YL L WSB MRN

3. PN NYLN

4. S GTP P PRSLN LYHR TSC LBBN D

5. YST RDY

6. GTBC K

7. BL DB LD

8. LTT B

9. GH TDY SWK

10. FLFN

As usual you can post the answers as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

Answer on 9.00 on Monday

]]>You will see three phrases, one at a time. These are now below. You have to work out the fourth phrase.

The three are:

*2019 C*

*2018 É*

*2016 E*

The years refer to the most recent Six Nations Grand Slams, and the letters are the name of the winning country in its own language - C for Cymru (Wales), É for Éireann (Ireland) and E for England (England). The Grand Slam before 2016 was in 2012, which was won by Wales and so the fourth in the sequence is

*2012 C*

You will see three phrases, one at a time. These are now below. You have to work out the fourth phrase.

The three are:

*2019 C*

*2018 É*

*2016 E*

Answer at 9.00 on Monday

]]>You will see three phrases, one at a time. The first two are below, and the third will be revealed in an hour. You have to work out the fourth phrase. Obviously, the more that you see, the easier it should be.

The first two are:

*2019 C*

*2018 É*

Answer at 9.00 on Monday

]]>You will see three phrases, one at a time. The first is below, and the other two will be revealed at hourly intervals. You have to work out the fourth phrase. Obviously, the more that you see, the easier it should be.

The first one is:

*2019 C*

Answer at 9.00 on Monday

]]>The father weighs 90 kg, the mother weighs 80 kg, the elder child weighs 60 kg, the younger child weighs 40 kg, and they have a dog that weighs 20 kg.

Assuming that the humans can all paddle the canoe, how do they cross the river?

It is obvious that the father must travel alone, that the mother can take the dog, and the children can travel together. So the puzzle revolves around who takes the canoe back to minimise crossings.

Here is one variation:

The two children paddle across and the elder one returns

The father paddles across and the younger child returns

The two children cross again and the elder one returns

The mother takes the dog across and the younger child returns

The two children paddle over for the last time

]]>The father weighs 90 kg, the mother weighs 80 kg, the elder child weighs 60 kg, the younger child weighs 40 kg, and they have a dog that weighs 20 kg.

Assuming that the humans can all paddle the canoe, how do they cross the river?

Answer on 9.00 on Monday

]]>- 57 HV - 57 Heinz Varieties
- 1760 Y in a M - 1760 Yards in a Mile
- 6 F on a C - 6 Faces on a Cube
- 7 P for the B in S - 7 Points for the Black in Snooker
- 8 P in the SS - 8 Planets in the Solar System
- 2 4 6 8 M - 2 4 6 8 Motorway
- The J 5 - The Jackson 5
- 240 P in a P - 240 Pennies in a Pound
- 2 G of V - 2 Gentlemen of Verona
- 16 GO 17 - 16 Going On 17

- 57 HV
- 1760 Y in a M
- 6 F on a C
- 7 P for the B in S
- 8 P in the SS
- 2 4 6 8 M
- The J 5
- 240 P in a P
- 2 G of V
- 16 GO 17

Answer on 9.00 on Monday

]]>After walking for a while he comes to a river which he crosses quite easily, and then carries on in the direction that he believes to be correct.

After walking further he comes to a river which looks exactly the same as the river that he crossed earlier. Everything about this river is indistinguishable from the other river.

And yet the explorer knows with complete certainty that this is a different river - how?

Very simply, both are flowing the same direction with respect to the explorer. If you cross a river flowing right to left, if you cross it again it has to be flowing left to right.

]]>After walking for a while he comes to a river which he crosses quite easily, and then carries on in the direction that he believes to be correct.

After walking further he comes to a river which looks exactly the same as the river that he crossed earlier. Everything about this river is indistinguishable from the other river.

And yet the explorer knows with complete certainty that this is a different river - how?

Answer on 9.00 on Monday

]]>The Puzzle is here

- Robin DAY
- TREE
- CAROL Vorderman
- CAKE
- Traffic ISLAND
- EVE Goddard
- Jimmy WHITE
- High JUMPER
- ROSE

Answers 1-6, 8 and 9 can all be preceded by Christmas - Christmas Day, Christmas Tree etc.

Only 7 (White) comes before Christmas - White Christmas

]]>The Puzzle is here

Answer on 9.00 on Monday 6th January

]]>Mr and Mrs Smith have four daughters, each of whom have a husband, two brothers and two sons.

How many people should we expect, so we can work out the size of our turkey?

Actually only four.

Each of the Smiths daughters will have taken her husband's surname, and thus her sons will have that surname too. So the four Smiths are Mr and Mrs Smith and their two sons, who are the brothers of their daughters.

Yes, we do know that nowadays woman don't necessarily take their husband's surname, and that the husbands could be called Smith; however this is a Christmas puzzle, so please don't shout.

]]>Mr and Mrs Smith have four daughters, each of whom have a husband, two unmarried brothers and two sons.

How many people should we expect, so we can work out the size of our turkey?

Answer on 9.00 on Monday

]]>