Regardless of how you describe it, the challenge this week is to cut a doughnut into as many pieces as possible using only three straight cuts. The pieces do not have to be the same size or the same shape; you just have to get as many as you can.

How many pieces can you produce?

As usual you can post your suggested answers as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

Answers at 9.00 on Monday

]]>One of the Quiz Master Shop question writers went on holiday to a secluded seaside village, and returned with a very neatly trimmed beard. He had visited the barber who was extremely good, and in the manner of these things they had fallen into conversation.

Oddly, there were no bearded men in the village, and the barber shaved every man who didn't shave himself.

So, who shaves the barber.

At first this seems like a paradox; if the barber doesn't shave himself he must be shaved by the barber, and if the barber does shave himself he must be someone who isn't shaved by the barber.

Except if the barber is a woman

]]>One of the Quiz Master Shop question writers went on holiday to a secluded seaside village, and returned with a very neatly trimmed beard. He had visited the barber who was extremely good, and in the manner of these things they had fallen into conversation.

Oddly, there were no bearded men in the village, and the barber shaved every man who didn't shave himself.

So, who shaves the barber.

As usual you can post your suggested answers as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

Answers at 9.00 on Monday

]]>1. L VMT NDR

Love Me Tender

2. LVC TLLY

Love Actually

3. CR TN YLV

Courtney Love

4. H WDL VTH? L TMCN TT HWYS

How Do I Love Thee? Let Me Count The Ways

5. L VSL BRSL ST

Love's Labours Lost

6. MN TNL V

I'm Not In Love

7. L VLT TRS

Love Letters

8. DV SLV III

Davis Love III

9. LVMN SNT HNGT TN NSP LYR

Love Means Nothing To A Tennis Player

10. LVM D

Love Me Do

]]>1. L VMT NDR

2. LVC TLLY

3. CR TN YLV

4. H WDL VTH? L TMCN TT HWYS

5. L VSL BRSL ST

6. MN TNL V

7. L VLT TRS

8. DV SLV III

9. LVMN SNT HNGT TN NSP LYR

10. LVM D

As usual you can post your suggested answers as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

Answers at 9.00 on Monday

]]>There are four three-digit numbers that equal the sum of the cubes of their digits, and your challenge is to find them.

For example, with 123, 1 cubed + 2 cubed +3 cubed = 1 + 8 + 27 = 36, which doesn't work. But there are four numbers that do work - can you find them?

The numbers are:

153: 1 cubed + 5 cubed + 3 cubed = 1 + 125 + 27 = 153

370: 3 cubed + 7 cubed + 0 cubed = 27 + 343 + 0 = 370

371: 3 cubed + 7 cubed + 1 cubed = 27 + 343 + 1 = 371

407: 4 cubed + 0 cubed + 7 cubed = 64 + 0 + 343 = 407

How many did you get?

]]>

There are four three-digit numbers that equal the sum of the cubes of their digits, and your challenge is to find them.

For example, with 123, 1 cubed + 2 cubed +3 cubed = 1 + 8 + 27 = 36, which doesn't work. But there are four numbers that do work - can you find them?

Answers at 9.00 on Monday

]]>What show has he been binge-watching recently?

Below are the episode titles:

- Idiots
- Take-off and landing locale
- Cardboard container
- Perishes
- Three-valved brass instrument
- One throwing a party
- Fibs

But the descriptions here have got mixed up:

- Citrus fruits
- Fresh Prince of Bel-Air character
- Fugitive
- Latter Day Saint members
- Prepares foods into cubes
- Small crown
- The Planets suite composer

Match the descriptions to the titles and deduce the show.

The episode title answers are: MORONS, RUNWAY, CARTON, DIES, CORNET, HOST, LIES.

The description answers are, in given order: LIMES, CARLTON, RUNAWAY, MORMONS, DICES, CORONET, HOLST.

The descriptions can be paired up with episode titles when one extra letter is added into the episode title. MORONS becomes MORMONS, for example. HOST becomes HOLST. The extra letters in episode order are M, A, L, C, O, L, M. Also note that (as shown below) these letters are in the exact middle of the descriptions:

MOR**M**ONS

RUN**A**WAY

CAR**L**TON

DI**C**ES

COR**O**NET

HO**L**ST

LI**M**ES

Thus the show that he's been binge-watching recently is **MALCOLM IN THE MIDDLE**.

**Note**: Local Lockdown rules are changing weekly

Monday 1st - Hemingways 20.00

Tuesday 2nd - Not Just An Udder Quiz (Online) 19.40

Wednesday 3rd - Robbie's Quarantine Quiz (Online) 20.00

Thursday 4th - Frank Paul (Online) 20.00

Sunday 7th - Angus Walker (Online) 19.00

Monday 8th - Hemingways 20.00

Tuesday 9th - Not Just An Udder Quiz (Online) 19.40

Thursday 11th - Frank Paul (Online) 20.00

Monday 15th - Hemingways 20.00

Tuesday 16th - Not Just An Udder Quiz (Online) 19.40

Wednesday 17th - Robbie's Quarantine Quiz (Online) 20.00

Thursday 18th - Frank Paul (Online) 20.00

Sunday 21st - Angus Walker (Online) 19.00

Monday 22nd - Hemingways 20.00

Tuesday 23rd - Not Just An Udder Quiz (Online) 19.40

Thursday 25th - Frank Paul (Online) 20.00

]]>

We are pleased to announce that this pre-eminence has been recognised in the Welsh Enterprise Awards, and we have received Best Quiz Download Platform 2020.

See details here

So come and try Quiz Master Shop and

**Get What You Want, Not What You're Given**

Many thanks to our partner NDS for there work in achieving this.

]]>What show has he been binge-watching recently?

Below are the episode titles:

- Idiots
- Take-off and landing locale
- Cardboard container
- Perishes
- Three-valved brass instrument
- One throwing a party
- Fibs

But the descriptions here have got mixed up:

- Citrus fruits
- Fresh Prince of Bel-Air character
- Fugitive
- Latter Day Saint members
- Prepares foods into cubes
- Small crown
- The Planets suite composer

Match the descriptions to the titles and deduce the show.

Answers at 9.00 on Monday

]]>This time you are not required to produce sums, but rather descriptions of the numbers.

One has Three letters, Two also has Three letters, Three has Five letters, and Four has Four letters, and is the only number that has this property. What you have to do is produce phrases that describe a number in that number of letters, for as many numbers as possible.

The descriptions must be universal; you can't have "The number bus I catch to work" for 24. And from this you can deduce that spaces don't count, only letters.

See how many you can get.

Here is the list we have. Some might be considered a bit "iffy", but we have a list up to 25.

1 = I

2 = Bi

3 = Tri

4 = Four

5 = A Five

6 = One Six

7 = Six Et Un

8 = Two Cubed

9 = One Off Ten

10 = Nine And One

11 = Nine Plus Two

12 = Nine And Three

13 = Twelve Plus One

14 = Thirteen And One

15 = One Half Of Thirty

16 = Thirteen And Three

17 = Four Squared And One

18 = One Half Of Thirty Six

19 = Half Of Forty Minus One

20 = One Half Of Twice Twenty

21 = One Times Eleven Plus Ten

22 = Two Times Eleven Plus Zero

23 = Four Plus Four Plus Fifteen

24 = Five Squared And One Removed

25 = Five Squared With Zilch Added

]]>This time you are not required to produce sums, but rather descriptions of the numbers.

One has Three letters, Two also has Three letters, Three has Five letters, and Four has Four letters, and is the only number that has this property. What you have to do is produce phrases that describe a number in that number of letters, for as many numbers as possible.

The descriptions must be universal; you can't have "The number bus I catch to work" for 24. And from this you can deduce that spaces don't count, only letters.

See how many you can get.

Answers at 9.00 on Monday

]]>Blue | White | Scarlet | Mustard |

Red | Black | Silver | Pepper |

Goose | Head | Chore | Late |

Pigeon | Mile | Rasp | Yarg |

Goose, Rasp, Blue and Black - Berries

Red, Silver, White and Head - can precede Lining

Pigeon, Pepper, Mustard and Scarlet - can go after an army rank (Lieutenant Pigeon, Sergeant Pepper, Colonel Mustard and Captain Scarlet)

Yarg, Late, Chore and Mile - anagrams of colours (Gray, Teal, Ochre and Lime)

]]>Blue | White | Scarlet | Mustard |

Red | Black | Silver | Pepper |

Goose | Head | Chore | Late |

Pigeon | Mile | Rasp | Yarg |

Answer at 9.00 on Monday

]]>You have two ropes and you know that each rope will take exactly one hour to burn completely. The bad news is that the rate of burn along the ropes is inconsistent; parts of them will burn more quickly and other parts will burn more slowly, and both ropes are different.

But you do know that the total burn time for both ropes is sixty minutes, even if you can't assume that when half of the length is burnt, 30 minutes have elapsed.

The challenge is to measure exactly three quarters of an hour (45 minutes) using these two ropes and as many matches as you want.

Light one end of one of the ropes and both ends of the other rope.

When the second rope has burnt out exactly 30 minutes will have passed, and you light the unlit end of the other rope.

As the first rope had been burning for 30 minutes it would have to have 30 minutes of burning time left. And as it is now burning from both ends it will burn out 45 minutes after you started.

]]>Do you serve food on your Quiz Nights? Lots of places do with some tables eating during the quiz and some tables not doing so.

This can get a little awkward with tables having food delivered during one of the Quiz rounds. The inevitable “Can I get you any sauces?” means that the team didn’t hear a question or two. And then they are all eating while trying to answer questions, which can be difficult.

Have you thought of a Quiz and Supper bundle?

For example, you can provide a main course and the quiz for a fixed price, which might encourage more quizzers to partake of food. (And meets the Substantial Meal requirement) Everyone places their orders before the quiz starts (while doing the table round – see a previous Tip) and the food is delivered during the interval (and eaten while doing the second table round). So there is much less disruption.

It’s your choice whether you make the bundle optional and allow people to do only the quiz, as and when lockdown rules allow.

]]>You have two ropes and you know that each rope will take exactly one hour to burn completely. The bad news is that the rate of burn along the ropes is inconsistent; parts of them will burn more quickly and other parts will burn more slowly, and both ropes are different.

But you do know that the total burn time for both ropes is sixty minutes, even if you can't assume that when half of the length is burnt, 30 minutes have elapsed.

The challenge is to measure exactly three quarters of an hour (45 minutes) using these two ropes and as many matches as you want.

As usual you can post your answer as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

We’ll give the answer and explanation on Monday at 9.00 as usual.

]]>There are five huts in which the turkey can hide numbered one to five, all in a row, and the turkey hides in one of them during the night. The pattern for the ensuing search is as follows:

- Each morning the farmer looks in one of the huts.
- If the turkey is in the hut the farmer locks the door, the turkey is trapped, and Christmas dinner is saved.
- If the hut is empty the farmer leaves and overnight the turkey moves to one of the adjacent huts. For example, if it is in hut two it must move to either hut one or hut three, and if it is in hut five it must move to hut four.
- The next morning the farmer has another look, and so on.

The farmer has only six mornings left to find the turkey. Can you devise a method that guarantees that the farmer will find the turkey within six searches?

Assume for the time being that the turkey hid the first night in an even numbered hut. That is hut two or hut four.

So the farmer looks in hut two on the first morning. If the turkey is there then the search is over, and if not, the turkey must be in hut four.

On the second morning, as the turkey must now be in hut three or hut five after its overnight move, the farmer looks in hut three. If the turkey is there then the search is over, and if not, the turkey must be in hut five.

On the third morning, as the turkey must now be in hut four after its overnight move, the farmer looks in hut four and finds the turkey.

So if we know the turkey is in an even numbered hut we can always catch the turkey within three searches. However, we can't guarantee the turkey started in an even numbered hut, so this will not catch the turkey if it started in an odd numbered hut.

The good news is that if the turkey started in an odd numbered hut, after three days (and three moves) it must now be in an even numbered hut, and it can be found within three more searches.

Searching in the order two, three, four, two, three and four must find the turkey within six searches.

]]>**Note**: Local Lockdown rules are changing weekly

Monday 4th - Hemingways 20.00 **Cancelled**

Tuesday 5th - Not Just An Udder Quiz Quiz of the Year (Online) 19.40

Wednesday 6th - Robbie's Quarantine Quiz (Online) 20.00

Sunday 10th - Angus Walker (Online) 19.00

Sunday 10th - The Inn on the Green 19.00 **Check with Pub**

Monday 11th - Hemingways 20.00

Tuesday 15th - Not Just An Udder Quiz (Online) 19.40

Thursday 14th - Frank Paul (Online) 20.00

Sunday 17th - Angus Walker (Online) 19.00

Sunday 17th - The Inn on the Green 19.00 **Check with Pub**

Monday 18th - Hemingways 20.00

Wednesday 20th - Robbie's Quarantine Quiz (Online) 20.00

Thursday 21st - Frank Paul (Online) 20.00

Sunday 24th - Angus Walker (Online) 19.00

Sunday 24th - The Inn on the Green 19.00 **Check with Pub**

Monday 25th - Hemingways 20.00

Thursday 28th - Frank Paul (Online) 20.00

Sunday 31st - Angus Walker (Online) 19.00

Sunday 31st - The Inn on the Green 19.00 **Check with Pub**

A farmer has raised several turkeys and has sold all but one of them. The remaining turkey is destined for the farmer's family's Christmas dinner. Unfortunately for the farmer (but maybe fortunately for the turkey) a week before Christmas the turkey realises what is going on and decides to hide.

There are five huts in which the turkey can hide numbered one to five, all in a row, and the turkey hides in one of them during the night. The pattern for the ensuing search is as follows:

- Each morning the farmer looks in one of the huts.
- If the turkey is in the hut the farmer locks the door, the turkey is trapped, and Christmas dinner is saved.
- If the hut is empty the farmer leaves and overnight the turkey moves to one of the adjacent huts. For example, if it is in hut two it must move to either hut one or hut three, and if it is in hut five it must move to hut four.
- The next morning the farmer has another look, and so on.

The farmer has only six mornings left to find the turkey. Can you devise a method that guarantees that the farmer will find the turkey within six searches?

As usual you can post your answer as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

We’ll give the answer and explanation on Monday 4th January at 9.00 as usual.

]]>Three people went out for a Christmas meal in a very nice restaurant. They had an excellent dinner with some quality wines and were presented with a bill for £300. (We did say it was a very nice restaurant!). They each paid their share of £100 and prepared to leave.

At this point the restaurant manager realised that there had been a terrible mistake, and the bill should have been £250. She summoned the waiter and gave him £50 in ten pound notes to give to the three customers as a refund. (Anyone would think it is Christmas – oh wait, it is)

Now the waiter was a bit disgruntled with these particular customers, as they hadn’t given him a tip despite paying a large sum of money for the meal. Furthermore, how were they going to split £50 between the three of them?

So the waiter pocketed two of the ten pound notes as a tip and handed the customers a ten pound note each. The customers left and everyone seemed to be happy with the situation – the customers had received a refund, the waiter had his tip, and the restaurant manager had been paid the correct amount. But should they have been so happy?

Each of the three customers had paid £90 for their share of the meal which makes £270. And the waiter has £20 which makes £290 in total. But the diners paid £300, so where is the missing ten pound note?

As with many puzzles of this sort, like many pieces of “magic”, the trick is to spot the misdirection. In this case the £270 that the customers paid includes the £20 in the waiter’s pocket. So adding the two sums together is meaningless, rendering the comparison with the original £300 equally meaningless.

Consider the following sequence:

- Customers pay £300 – the restaurant has £300
- The manager gives £50 to the waiter – the restaurant has £250, the waiter has £50 and the customers have still paid £300
- The waiter gives the customers £30 – the restaurant still has £250, the waiter has £20 and the customers have paid £270

And this all balances.

]]>Three people went out for a Christmas meal in a very nice restaurant. They had an excellent dinner with some quality wines and were presented with a bill for £300. (We did say it was a very nice restaurant!). They each paid their share of £100 and prepared to leave.

At this point the restaurant manager realised that there had been a terrible mistake, and the bill should have been £250. She summoned the waiter and gave him £50 in ten pound notes to give to the three customers as a refund. (Anyone would think it is Christmas – oh wait, it is)

Now the waiter was a bit disgruntled with these particular customers, as they hadn’t given him a tip despite paying a large sum of money for the meal. Furthermore, how were they going to split £50 between the three of them?

So the waiter pocketed two of the ten pound notes as a tip and handed the customers a ten pound note each. The customers left and everyone seemed to be happy with the situation – the customers had received a refund, the waiter had his tip, and the restaurant manager had been paid the correct amount. But should they have been so happy?

Each of the three customers had paid £90 for their share of the meal which makes £270. And the waiter has £20 which makes £290 in total. But the diners paid £300, so where is the missing ten pound note?

As usual you can post your answer as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

We’ll give the answer and explanation on Monday morning at 9.00 as usual.

]]>Two farmers met in the pub after a Christmas farmers’ market and started discussing the day’s trade.

“I sold all my sprouts” said the first, “every last one of them”.

“That’s good” replied his friend, “how many did you bring?”

“That’s the odd thing, I can’t remember. But I do remember that in the first hour I sold six sevenths of the sprouts that I brought, plus a seventh of a sprout”

“It must have been awkward cutting a sprout . . .”

“Don’t be daft, I don’t cut them! And strangely, the pattern repeated itself. In the second hour I sold six sevenths of the sprouts I had left, plus a seventh of a sprout. Then in the third hour I sold six sevenths of the sprouts I had left, plus a seventh of a sprout. And finally in the fourth hour I sold six sevenths of the sprouts I had left, plus a seventh of a sprout. Then I came to the pub because I had no more sprouts”.

How many sprouts did the farmer bring to market?

And for those who like a bit more of a challenge – can you work out a general formula for the number of sprouts if this had gone on for five, six, seven hours or more?

The best way to tackle this is to work back from the final hour. The farmer started that hour with x sprouts and sold 6x/7 + 1/7 sprouts, and as he ended with no sprouts this must equal x.

So x - 6x/7 + 1/7 = (x-1)/7 = 0 and x = 1

At the start of the penultimate hour he has x sprouts and (x-1)/7=1 (as he ends the hour with one sprout) and x is eight.

At the start of the second hour he has x sprouts and (x-1)/7=8 (as he ends the hour with eight sprouts) and x is 57.

And at the start of the first hour he has x sprouts and (x-1)/7=57 (as he ends the hour with 57 sprouts) and he started with 400 sprouts.

The general formula for the number of sprouts is the sum of 7^{0} 7^{1} 7^{2} to 7^{n} where n is the number of hours minus one. With the four hours above this is 1+7+49+343 which is 400.

This number grows very quickly and to sell every sprout using this pattern over seven hours, the farmer would need to bring 137,257 sprouts.

]]>Two farmers met in the pub after a Christmas farmers’ market and started discussing the day’s trade.

“I sold all my sprouts” said the first, “every last one of them”.

“That’s good” replied his friend, “how many did you bring?”

“That’s the odd thing, I can’t remember. But I do remember that in the first hour I sold six sevenths of the sprouts that I brought, plus a seventh of a sprout”

“It must have been awkward cutting a sprout . . .”

“Don’t be daft, I don’t cut them! And strangely, the pattern repeated itself. In the second hour I sold six sevenths of the sprouts I had left, plus a seventh of a sprout. Then in the third hour I sold six sevenths of the sprouts I had left, plus a seventh of a sprout. And finally in the fourth hour I sold six sevenths of the sprouts I had left, plus a seventh of a sprout. Then I came to the pub because I had no more sprouts”.

How many sprouts did the farmer bring to market?

And for those who like a bit more of a challenge – can you work out a general formula for the number of sprouts if this had gone on for five, six, seven hours or more?

As usual you can post your answer as a comment on this website, reply to the post on Facebook , or retweet or reply on Twitter @quizmastershop.

We’ll give the answer and explanation on Monday morning at 9.00 as usual.

]]>ABCDE x A = EEEEEE

Looking at the E there are not that many digits that could be apart from 5, so the result of the sum is most likely 555555.

The single digit factors of 555555 are 3, 5 and 7. A can't be 5 as we think E is 5, and 555555 / 3 = 185185, a six-digit number.

555555 / 7 = 79365 a five-digit number with five different digits ending in 5, so the answer is . . .

79365 x 7 = 555555

]]>**Note**: Local Lockdown rules are changing weekly

Tuesday 1st - Not Just An Udder Quiz (Online) 19.40

Wednesday 2nd - Robbie's Quarantine Quiz (Online) 20.00

Thursday 3rd - Frank Paul (Online) 20.00

Sunday 6th - The Inn on the Green 19.00** Check with Pub**

Monday 7th - Hemingways 20.00

Tuesday 8th - Not Just An Udder Quiz (Online) 19.40

Thursday 10th - Frank Paul The Lion, The Witch and The Wardrobe Christmas Quiz (Online) 20.00

Sunday 13th - Angus Walker (Online) 19.00

Sunday 13th - The Inn on the Green 19.00 **Check with Pub**

Monday 14th - Hemingways 20.00

Tuesday 15th - Not Just An Udder Quiz Christmas Quiz (Online) 19.40

Sunday 20th - The Inn on the Green 19.00 **Check with Pub**

Monday 21st - Hemingways 20.00

Sunday 27th - The Inn on the Green 19.00 **Check with Pub**

Monday 28th - Hemingways 20.00

]]>ABCDE x A = EEEEEE

As usual you can post the answers as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

Answer at 9.00 on Monday

]]>The first said that she had realised that in the past the year was the square of her father's age at that time. Sadly her father had passed away at the age of 100 (another square, but not relevant to this puzzle).

The second remarked that by coincidence she expected the year to be the square of her age before her 100th birthday.

In which years were the first teacher's father and the second teacher born?

The first thing to do is to find years either side of 2001 that are square numbers. 44 x 44 = 1936 and 45 x 45 = 2025, so these are good candidates.

If the father was 44 in 1936 he was born in 1892 and died in 1992, with the first teacher being born after 1942 to be under 60.

The second teacher was born in 1980, and will be 45 in 2025.

We can rule out other square years. 43 x 43 = 1849 and if the father was born in 1806, and so died in 1906, he would have been dead by the earliest birth year for his daughter. And if the second teacher was to be 46 in 2116 (46 x 46) then he would not yet be born.

]]>The first said that she had realised that in the past the year was the square of her father's age at that time. Sadly her father had passed away at the age of 100 (another square, but not relevant to this puzzle).

The second remarked that by coincidence she expected the year to be the square of her age before her 100th birthday.

In which years were the first teacher's father and the second teacher born?

As usual you can post the answers as a comment on this website, reply to the post on Facebook, or retweet or reply on Twitter @quizmastershop.

Answer at 9.00 on Monday

]]>