Two presents are to be given to two children at a birthday party.
The children are told to sit in a circle and a die (singular of dice, but you knew that!) is rolled, giving a number between one and six. Counting Eddy as number one, and going clockwise, the number on the die is used to determine the recipient of the first present.
That child stands up and is no longer in the circle, and rolls the die a second time. Starting with the child on the left of the winner, and again going clockwise, the number determines the second child to get a present.
As the children are originally seated, Vicky has the best chance of a present, and Pete the second-best chance. Rachel has the same chance as Eddy, and Paul's chances are the worst. However Kitty has four times as much chance as another child.
How are the named children seated?
As usual you can post your suggested answers as a comment on this website, reply to the post on Facebook or Instagram, or retweet or reply on X (formerly Twitter) @quizmastershop.
Answer at 9.00 on Monday